Find the value of the following polynomial at the indicated value of the variable: $q(y) = 3y^3 - 4y + \sqrt{11}$ at $y = 2$.

$(16+\sqrt{11})$ Given the polynomial $q(y) = 3y^3 - 4y + \sqrt{11}$.
To find the value of the polynomial at $y = 2$,we substitute $2$ for $y$ in the expression:
$q(2) = 3(2)^3 - 4(2) + \sqrt{11}$
Calculate the power: $2^3 = 8$.
Substitute back: $q(2) = 3(8) - 8 + \sqrt{11}$.
Perform multiplication: $q(2) = 24 - 8 + \sqrt{11}$.
Perform subtraction: $q(2) = 16 + \sqrt{11}$.